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1 road - x2 road - x3 road - x4 road - -1x
The Lengths of the 4 roads1 ~ x2 ~ x3 ~ x-84 ~ 7
1st - x2nd- x3rd- (x+6)4th- -7
road 4 -> -7???cannot be negative
A ROAD CAN NEVER BE -7!!! NO LOGIC. :D
How You Created a -7 Road?
It is not possible to have a road that is -7 in length.
The length of the 4 roads are: (1/2)x km, x km, (x-1) km, (1/2)x kmCheck: (1/2)x km + (1/2)x km + x km + (x-1)km =(3x-1)km
Road 1 - 1.2x kmRoad 2 - 0.7x kmRoad 3 - 1.1x kmRoad 4 - 1 km
1.2x km + 0.7x km + 1.1x km + 1km
You Don't have -1
Your current total is (3x+1)km not (3x-1)km
this does not add up to (3x-1)pootis!
There is no negative number (-1).
Road 1 - 1.5x kmRoad 2 - 1.5x kmRoad 3 - -1 kmRoad 4 - 2 km1.5x km + 1.5x km + -1km + 2km
where's "-1 " ???
Ryan shut up u the pootis.
so mean......by the way..... what is "shut up u the pootis?"
road 1= xroad 2= xroad 3= (x+19)road 4= -20
The length of the 4 roads are: x km, x km ,x-9km, 8kmx+x+(x-9)+8=3x-1
where ur question
x/2 + x/2 + x + (x-1)
the length of the roads are..........x,x,(x+2) and x-1check x+X+(x+2)+(x-1)=(3x-1) i think......... this is gonna be derped up again
The length of the 4 roads : 2x , x-8 , 6, 12x+(x-8)+6+1
The length of the 4 roads are 2x km,x-5 km,2km,2kmCheck:2x+(x-5)+2+2
tha length of the 4 roads are (x)km,(x)-8km,(x)-8km,15kmcheck (x)+[(x)-8]+[(x)-8]+15=[3(x)-1]
1st road:x2nd road:x3rd road:x4th road:(5-4)x+x+x+(5-4)
The length of the 4 roads are: 3x Km, x-4 km, x Km, 3 KmCheck: 3x + (-x-4) + x + 3 = 3x-1X = 1